28.26=3.14(r^2)

Solution for 28.26=3.14(r^2) equation:

28.26=3.14(r^2)

We move all terms to the left:

28.26-(3.14(r^2))=0

We get rid of parentheses

-3.14r^2+28.26=0

a = -3.14; b = 0; c = +28.26;
Δ = b2-4ac
Δ = 02-4·(-3.14)·28.26
Δ = 354.9456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{354.9456}}{2*-3.14}=\frac{0-\sqrt{354.9456}}{-6.28}
=-\frac{\sqrt{}}{-6.28}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{354.9456}}{2*-3.14}=\frac{0+\sqrt{354.9456}}{-6.28}
=\frac{\sqrt{}}{-6.28}
$